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20070201
k Hyperbolic and Inverse Hyperbolic Functions
• Be sure to specify Comp for Mode in the Setup screen.
Example Operation
sinh 3.6 = 18.28545536
K 6 (g )2 (HYP)1 (sinh) 3.6 w
cosh 1.5 – sinh 1.5
= 0.2231301601
=
e
–1.5
(Display: –1.5)
(Proof of cosh x ± sinh x = e
±
x
)
K 6 (g )2 (HYP)2 (cosh) 1.5 -
1 (sinh) 1.5 w
I!- (Ans)w
cosh
–1
20
15
= 0.7953654612
<Line>
K 6 (g )2 (HYP)5 (cosh
–1
)( 20 / 15 ) w
<Math>
K 6 (g )2 (HYP)5 (cosh
–1
)$ 20 c 15 w
Determine the value of
x
when tanh 4 x = 0.88
x =
tanh
–1
0.88
4
= 0.3439419141
<Line>
K 6 (g )2 (HYP)6 (tanh
–1
) 0.88 / 4 w
<Math>
$ K 6 (g )2 (HYP)6 (tanh
–1
) 0.88 c 4 w
2-4-6
Function Calculations