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MELSEC-Q
12 CONTROL SUB FUNCTIONS
Thus, AP, AL and AM
to be set are as follows.
AP
= 180224 ……
Pr.2
AP
= 180224 …
Pr.2
AL
= 67.50000 …
Pr.3
or AL
= 0.06750 …
Pr.3
AM
= 1 ………..…
Pr.4
AM
= 1000 …….
Pr.4
Note): These two examples of settings are only examples. There are
settings other than these examples.)
(4) When "mm" is set as the control unit for conveyor drive
(calculation including
)
When the belt conveyor drive is used, the conveyor diameter is 135mm,
the pulley ratio is 1/3, the motor is HF-KP (262144PLS/rev) and the
reduction ratio of the reduction gear is 7/53.
Reduction ratio 7/53
M
Belt conver
Pulley ratio 1/3
135mm
As the travel value of the conveyor is used to exercise control, set "mm"
as the control unit.
First, find how many millimeters the load (machine) will travel (
S
) when
the motor turns one revolution (AP).
•
AP(No. of pulses per rotation) = 262144
•
S
(Machine travel value per motor revolution)
= 135000.0 [
µ
m]
×
×
Reduction ratio
= 135000.0 [
µ
m]
×
×
7/53
×
1/3
Substitute this for the above expression (1).
At this time, make calculation with the reduction ratio 7/53
×
1/3 remaining
as a fraction.
AP AP 262144 [PLS]
S
=
AL
×
AM
=
135000.0 [
µ
m]
×
×
7/53
×
1/3
262144
×
53
×
3
=
135000.0
×
×
7
Here, make calculation on the assumption that
is equal to
3.141592654.
AP AP 41680896
S
=
AL
×
AM
=
2968805.058